A) 4000
B) 2000
C) 1000
D) None of these
Correct Answer: B
Solution :
Here, input resistance, \[{{R}_{i}}=50\,\Omega \] Change in base current, \[\Delta {{l}_{B}}=20\mu A=20\,\,\times \,1{{0}^{-\,6}}A\] Change in collector current, \[\Delta {{l}_{C}}\,\,=\,\,1mA\,\,=1\,\,\times \,\,{{10}^{-\,3}}\,A\] Load resistance \[{{R}_{L}}\,\,=\,\,2\,k\,\Omega \,\,=\,\,2\times 1{{0}^{3}}\,\Omega \] Current gain \[\beta =\frac{\Delta {{l}_{C}}}{\Delta {{l}_{B}}}=\frac{1\times {{10}^{-\,3}}}{20\times {{10}^{-\,6}}}\,\,=\,\,50\] Voltage gain of the amplifier is \[{{A}_{V}}=\beta \frac{{{R}_{L}}}{{{R}_{i}}}=50\times \frac{2\times {{10}^{3}}}{50}=2000\]
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