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NEET Sample Paper NEET Sample Test Paper-81

  • question_answer
    A 500 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 500 pF capacitor. The loss of electrostatic energy in this process is

    A)  \[2\,\,\times \,\,1{{0}^{-\,6}}\,V\]                     

    B)  \[3\,\,\times \,\,1{{0}^{-\,6}}\,V\]

    C)  \[5\,\,\times \,\,1{{0}^{-\,6}}\,V\]                     

    D)  \[6\,\,\times \,\,1{{0}^{-\,6}}\,V\]

    Correct Answer: C

    Solution :

    Here, \[{{\operatorname{C}}_{1}} = {{C}_{2}} = 500 pF = 500 \times \,\,1{{0}^{-}}^{12}\,{{l}^{2}}= 5 \times 1{{0}^{-}}^{10}\,F\] Now, \[{{\operatorname{V}}_{1}}=200V,\,\,{{V}_{2}}=0\] \[\therefore \,\,\,Energy\text{ }lost=\frac{{{C}_{1}}{{C}_{2}}{{({{V}_{1}}-{{V}_{2}})}^{2}}}{2({{C}_{1}}+{{C}_{2}})}\] \[=\,\,\frac{5\times {{10}^{-\,10}}\times 5\times {{10}^{-\,10}}{{(200-0)}^{2}}}{2(5\times {{10}^{-\,10}}+5\times {{10}^{-\,10}})}\,\,=\,\,5\times {{10}^{-\,6}}\,V\]


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