A) 200 V, 50 Hz
B) 400 V, 100 Hz
C) 100 V, 50 Hz
D) 150 V, 100 Hz
Correct Answer: A
Solution :
Turns of primary winding, \[{{N}_{p}}=500\] Turns of secondary winding, \[{{N}_{s}}=5000\] Primary winding voltage, \[{{E}_{p}}=\,\,20V\] Now, \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{E}_{s}}}{{{E}_{p}}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{5000}{500}=\frac{{{E}_{s}}}{20}\] Here, frequency will remain same. \[\therefore \] Secondary winding will have an output of 200V, 50 Hz.
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