A) 20, 80
B) 40, 60
C) 60, 40
D) 80, 20
Correct Answer: A
Solution :
Let \[%\] of isotope with atomic weight \[10.01 = x%\]of isotope with atomic weight \[11.01 = \left( 100 - x \right)\] Since, atomic weight \[=\,\,\frac{x\,\,\times \,\,10.01+\left( 100-x \right)\,\,\times \,\,11.01}{100}\] \[10.81\,\,=\,\,\frac{x \times \,\,10.01+\left( 100-x \right)\,\,\times \,\,11.01}{100}\] \[x=20\] Hence, \[%\] of isotope with atomic weight \[10.01\text{ }=\text{ }20\] % of isotope with atomic weight 11.01 \[=100-20\] \[=\,\,80\]You need to login to perform this action.
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