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NEET Sample Paper NEET Sample Test Paper-81

  • question_answer
    A parallel plate air capacitor is charged to a potential difference of V volt. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result potential difference between the plates

    A)  decreases                     

    B)  increases

    C)  becomes zero    

    D)  does not change

    Correct Answer: A

    Solution :

    Capacitance, \[C=\frac{V}{q}\] \[\left[ V = potential difference,\,\,q =charge \right]\] Also capacitance, \[C=\frac{{{\varepsilon }_{0}}A}{d}\] \[\left[ A = area of plate,d =distance between plates \right]\] As d increases capacitance decreases according to \[C=\frac{{{\varepsilon }_{0}}A}{d}\] and battery is disconnected, so charge is constant. \[\therefore \] Potential difference decreases according to\[C=\frac{V}{q}\].


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