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NEET Sample Paper NEET Sample Test Paper-81

  • question_answer
    A beaker contains water up to a height \[{{h}_{2}}\] and another non-miscible liquid upto height h 3 above water so that the total height of (water + non-miscible liquid) is \[({{h}_{1}}+{{h}_{2}})\]. Refractive index of water is \[{{\mu }_{1}}\] and that of non-miscible liquid is p, 2. \[{{\mu }_{2}}\]. The apparent shift in the position of bottom of the beaker when viewed from above is

    A)  \[\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{2}}+\left( 1-\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{1}}\]

    B)  \[\left( 1+\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1+\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{2}}\]

    C)  \[\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1-\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{2}}\]

    D)  \[\left( 1+\frac{1}{{{\mu }_{1}}} \right){{h}_{2}}+\left( 1+\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{1}}\]

    Correct Answer: C

    Solution :

    Apparent shift \[\Delta h=\left( 1-\frac{1}{u} \right)h\] \[\therefore \] Apparent shift produced in water is \[\Delta {{h}_{1}}=\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}\]and apparent shift produced , by liquid is \[\Delta {{h}_{2}}\,=\,\,\left( 1-\frac{1}{{{\mu }^{2}}} \right){{h}_{2}}\] \[\Delta h\,\,=\,\,\Delta {{h}_{1}}+\Delta {{h}_{2}}=\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1-\frac{1}{{{\mu }^{2}}} \right){{h}_{2}}\]


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