A) \[2\,\,\times \,\,1{{0}^{-\,6}}\,V\]
B) \[3\,\,\times \,\,1{{0}^{-\,6}}\,V\]
C) \[5\,\,\times \,\,1{{0}^{-\,6}}\,V\]
D) \[6\,\,\times \,\,1{{0}^{-\,6}}\,V\]
Correct Answer: C
Solution :
Here, \[{{\operatorname{C}}_{1}} = {{C}_{2}} = 500 pF = 500 \times \,\,1{{0}^{-}}^{12}\,{{l}^{2}}= 5 \times 1{{0}^{-}}^{10}\,F\] Now, \[{{\operatorname{V}}_{1}}=200V,\,\,{{V}_{2}}=0\] \[\therefore \,\,\,Energy\text{ }lost=\frac{{{C}_{1}}{{C}_{2}}{{({{V}_{1}}-{{V}_{2}})}^{2}}}{2({{C}_{1}}+{{C}_{2}})}\] \[=\,\,\frac{5\times {{10}^{-\,10}}\times 5\times {{10}^{-\,10}}{{(200-0)}^{2}}}{2(5\times {{10}^{-\,10}}+5\times {{10}^{-\,10}})}\,\,=\,\,5\times {{10}^{-\,6}}\,V\]You need to login to perform this action.
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