A) (i) and (ii) only
B) (ii) and (iii) only
C) (i) and (iii) only
D) All of these
Correct Answer: C
Solution :
\[C{{o}^{3\,+}}\,and\,\,F{{e}^{2\,+}}\] contains \[{{d}^{6}}\] configuration and the unpaired electrons are paired by strong field ligands, i.e., \[N{{H}_{3}}\] and \[C{{N}^{-}},\,\,{{\left[ CO{{(N{{H}_{3}})}_{6}} \right]}^{3\,+}}\] and \[{{\left[ Fe{{(CN)}_{6}} \right]}^{4\,-}}\] are diamagnetic complexes. In \[F{{e}^{3\,+\,}}\] and \[M{{n}^{3\,+\,}}\] unpaired electrons remain even, after pairing, so there are paramagnetic.You need to login to perform this action.
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