A) - 3.8
B) + 3.8
C) - 1.9
D) + 1.9
Correct Answer: D
Solution :
Given that \[{{C}_{diamond}}+{{O}_{2}}\xrightarrow[{}]{}\,\,C{{O}_{2}},\,\,\Delta H=395.3\,kJ/mol\]\[{{C}_{graphite}}+{{O}_{2}}\xrightarrow[{}]{}\,\,C{{O}_{2}},\,\,\Delta H=-393.4\,kJ/mol\] eqs. (i)-(ii) \[{{C}_{diamond}}\xrightarrow{{}}{{C}_{graphite}}\] \[\Delta H = \Delta {{H}_{1}} - \Delta {{H}_{2}}\] \[= \,395.3 - 393.4 = 1.9 kJ mo{{l}^{-}}^{1}\]You need to login to perform this action.
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