A) \[\frac{17\,R}{6}\]
B) \[\frac{11\,R}{6}\]
C) 4R
D) \[\frac{3\,R}{2}\]
Correct Answer: A
Solution :
\[{{C}_{{{p}_{1}}}}(He)=\frac{5}{2}R,\,\,{{C}_{{{p}_{2}}}}({{H}_{2}})=\frac{7}{2}\,R\] \[{{n}_{He}}=2,\,\,{{n}_{{{H}_{2}}}}=1\] \[{{C}_{p}}=\frac{2\times \frac{5}{2}R+1\times \frac{7}{2}R}{3}=\frac{17\,R}{6}\]
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