A) \[\sqrt{2}\,m\,v\]
B) 2m v
C) \[\frac{\sqrt{2}\,m\,v}{2}\]
D) None of these
Correct Answer: C
Solution :
At point O, \[{{\operatorname{v}}_{1}} = v cos\,\hat{i}\,\,+\,\,v\,sin\,\theta \,\hat{j}\] At point O, \[{{\operatorname{v}}_{f}} = v cos\,\hat{i}\,\,\theta \,\hat{i}\] Now, \[\Delta p=m\left( {{v}_{f}}-{{v}_{i}} \right)\,\,=\,\,-mv\,\,sin\,\theta \,\hat{j}\] \[\left| \Delta p \right|\,\,=\,\,m v\,sin \theta \,\hat{j} =\,\,m\,v\,\,sin 45{}^\circ \] \[=\,\,\,\frac{mv}{\sqrt{2}}\,\,=\,\,\frac{\sqrt{2}mv}{2}\]You need to login to perform this action.
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