A) 273 K
B) 373 K
C) \[37{}^\circ C\]
D) \[110{}^\circ C\]
Correct Answer: B
Solution :
We know that at equilibrium \[\Delta G = 0\] for given reaction \[{{H}_{2}}O(l)\,\,\,\,{{H}_{2}}O\,(v)\] At equilibrium \[\Delta G = 0\] \[\Delta H\,\,-T\Delta S=0\] \[\Delta \text{H = T}\Delta \text{S}\] \[T=\frac{\Delta H}{\Delta S}=\frac{40.73\,kJ\,mo{{l}^{-\,1}}}{0.109\,kJ\,mo{{l}^{-\,1}}\,\,{{K}^{-\,1}}}\]\[=\,\,\,373\,K\]You need to login to perform this action.
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