A) 2 mA
B) 4 mA
C) 6 mA
D) 1 mA
Correct Answer: C
Solution :
Voltage across \[2 k\Omega \,resistor =12 V\] Therefore, current passing through \[2 k\Omega \] resistor \[=\,\,\,\frac{12}{2\times {{10}^{3}}}=6\times {{10}^{-\,3}}\,A=6\,mA\]
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