A) 0.3568 atm
B) 0.4936 atm
C) 0.1562 atm
D) 0.5623 atm
Correct Answer: B
Solution :
Given, \[\operatorname{c}= 0.02 M= 0.01 mol/2\] \[R = 0.0821 L-atm / degree / mol\] \[T=\,\,300\,K\] \[\pi =cRT=0.02 \times 0.0821 \times 300\] \[= \,0.4936 atm\]You need to login to perform this action.
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