A) 150 m/s
B) 75 m/s
C) 600 m/s
D) 300 m/s
Correct Answer: A
Solution :
As, \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\,\,\,\Rightarrow \,\,300=\sqrt{\frac{3RT}{M}}\] ... (i) and \[v{{'}_{rms}}=\sqrt{\frac{3R(T/2)}{2M}}\] ? (ii) On solving \[\operatorname{v}{{'}_{rms}} =\,\,150m/s\]You need to login to perform this action.
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