NEET Sample Paper NEET Sample Test Paper-82

  • question_answer
    The distance of a planet P from sun is 5.2 times that earth, then time period of revolution of P around the sun is

    A)  5.8 years                     

    B)  11.86 years

    C)  15.8 years                    

    D)  None of these

    Correct Answer: B

    Solution :

    Let \[{{r}_{e}}\,\,and\,{{r}_{P}}\] be distance of earth and planet P from the sun and \[{{\operatorname{T}}_{e}}\,\,and\,\,{{T}_{p}}\] be time period of revolution of earth and planet P around the sun.                       Now,     \[\frac{T_{P}^{2}}{T_{e}^{2}}=\frac{r_{P}^{2}}{r_{e}^{2}}\,\,\,\Rightarrow \,\,\,\,\,\,\,\,{{T}_{P}}={{T}_{e}}{{\left( \frac{{{r}_{e}}}{{{r}_{e}}} \right)}^{3/2}}\] \[=\,\,1{{\left( \frac{5.2\,re}{{{r}_{e}}} \right)}^{3/2}}[{{T}_{e}}=1\,year,\,\,\,{{r}_{P}}=5.2\,{{r}_{e}}]\] \[=\,\,\,11.86 year\]


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