A) \[70\,%\text{ }and\text{ }30\,%\]
B) \[85\,% and 15\,%\]
C) \[19.8\,% and 80.2\,%\]
D) \[90\,% and 10\,%\]
Correct Answer: C
Solution :
Let sample of boron having atomic mass 10.01 is \[x\,%\]. Sample of boron having atomic mass 11.01 is \[\] \[\left( 100 -x \right)%\] Average atomic weight \[=\,\,\frac{\operatorname{x}\,\,\times 10.01 + \left( 100-x \right)\times 11.01}{100}\] \[x=19.80%\] \[\therefore 100-x=100-19.8=80.20%\]You need to login to perform this action.
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