A) \[\frac{1}{2}th\]
B) \[\frac{1}{4}th\]
C) \[\frac{1}{8}th\]
D) None of these
Correct Answer: B
Solution :
As, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{\frac{t}{{{t}_{1/2}}}}}\Rightarrow \,\,\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{\frac{25}{12.5}}}\] \[\frac{N}{{{N}_{0}}}=\frac{1}{4}\,\,\,\Rightarrow \,\,\,\,N\,\,=\,\,\frac{{{N}_{0}}}{4}\]You need to login to perform this action.
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