A) \[N{{a}_{2}}O\]
B) \[S{{O}_{2}}\]
C) \[C{{O}_{2}}\]
D) \[A{{l}_{2}}{{O}_{3}}\]
Correct Answer: A
Solution :
\[{{\operatorname{Na}}_{2}}O + {{H}_{2}}O \xrightarrow{{}}\,\,NaOH\] \[{{\operatorname{SO}}_{2}} + {{H}_{2}}O \xrightarrow{{}}\,\,{{H}_{2}}S{{O}_{3}}\] \[\operatorname{C}{{O}_{2}} + {{H}_{2}}O \xrightarrow{{}}\,\,{{H}_{2}}C{{O}_{3}}\] \[{{\operatorname{Al}}_{2}}{{O}_{3}} + {{H}_{2}}O \xrightarrow{{}}\,\,Al{{\left( OH \right)}_{3}}\] NaOH is the most basic among the above compound.
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