A) \[10\,%\]
B) \[15\,%\]
C) \[20\,%\]
D) \[53\,%\]
Correct Answer: D
Solution :
Given, \[\operatorname{M} = 92, m= 40,n =2\] Degree of dissociation \[=x=\frac{M-m}{(n-1)m}\] \[=\,\,\,\,\frac{92-60}{(2-1)\times 60}=\frac{32}{60}\] \[=\,\,\,0.53\] % dissociation = 0.53 x 100 = 53%You need to login to perform this action.
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