NEET Sample Paper NEET Sample Test Paper-82

  • question_answer
    For the chemical reaction\[{{\operatorname{N}}_{2}}{{O}_{4}}(g)\,\,=\,\,-\,2N{{O}_{2}}(g)\] The observed molecular weight of \[{{\operatorname{N}}_{2}}{{O}_{4}}\] is \[60 g mo{{l}^{-}}^{1}\] at 300 K. The percentage dissociation of \[{{\operatorname{N}}_{2}}{{O}_{4}}\] (g) at 300 K is

    A)  \[10\,%\]                      

    B)  \[15\,%\]

    C)  \[20\,%\]                      

    D)  \[53\,%\]

    Correct Answer: D

    Solution :

    Given, \[\operatorname{M} = 92, m= 40,n =2\] Degree of dissociation \[=x=\frac{M-m}{(n-1)m}\] \[=\,\,\,\,\frac{92-60}{(2-1)\times 60}=\frac{32}{60}\] \[=\,\,\,0.53\] % dissociation = 0.53 x 100 = 53%


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