A) \[128.5 s c{{m}^{2}}\,mo{{l}^{-\,1}}\]
B) \[248 s c{{m}^{2}}\,mo{{l}^{-\,1}}\]
C) \[328 s c{{m}^{2}}\,mo{{l}^{-\,1}}\]
D) \[348 s c{{m}^{2}}\,mo{{l}^{-\,1}}\]
Correct Answer: A
Solution :
\[\Lambda _{NaCl}^{\infty }\,\,=\,\,\Lambda _{N{{a}^{+}}}^{\infty }\,\,+\,\,\Lambda _{C{{l}^{-}}}^{\infty }\,\,(126\,s\,\,c{{m}^{2}}\,mo{{l}^{-\,1}})\] ? (i) \[\Lambda _{KBr}^{\infty }\,\,=\,\,\Lambda _{{{K}^{+}}}^{\infty }\,\Lambda _{B{{r}^{-}}}^{\infty }\,\,(150\,s\,\,c{{m}^{2}}\,mo{{l}^{-\,1}})\] ? (ii) \[\Lambda _{KCl}^{\infty }\,\,=\,\,\Lambda _{{{K}^{+}}}^{\infty }+\,\Lambda _{C{{l}^{-}}}^{\infty }\,\,(150\,s\,\,c{{m}^{2}}\,mo{{l}^{-\,1}})\] ? (iii) Eqs. \[\left( i \right)+\left( ii \right)-\left( iii \right)\] \[\Lambda _{NaBr}^{\infty }\,\,=\,\,\Lambda _{N{{a}^{+}}}^{\infty }+\,\Lambda _{B{{r}^{-}}}^{\infty }\] \[=\,\,126+152-150=128\,\,s\,\,c{{m}^{2}}\,mo{{l}^{-\,1}}\]
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