A) Resolution
B) Clarity
C) Contrast
D) Magnification
Correct Answer: A
Solution :
Resolving power is given by \[n'=\frac{0.61\,\,\lambda }{n'\sin '\,\,\theta '}\]where, \[\operatorname{n}'\,\,sin\,\theta \,\,=\,\,NA\] (Numerical Aperture) and proportional to \[\lambda \] of light illominatioYou need to login to perform this action.
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