A) 4
B) 2
C) 1
D) 0.5
Correct Answer: B
Solution :
According to Graham?s law of diffusion, we know that \[{{r}_{dif}}\propto \frac{1}{\sqrt{M}},\,\,\frac{{{r}_{He}}}{{{r}_{C{{H}_{4}}}}}=\frac{{{M}_{C{{H}_{4}}}}}{{{M}_{He}}}=\sqrt{\frac{16}{4}}=2\]You need to login to perform this action.
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