A) \[\operatorname{A}<B<C\]
B) \[A<C<B\]
C) \[\operatorname{B}<C<A\]
D) \[\operatorname{C}<B<A\]
Correct Answer: B
Solution :
CFSE is higher when the complex contains strong field ligand. Thus, crystal field splitting energy increases in the order \[{{[CrC{{l}_{6}}]}^{3\,-}}\,<\,\,{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3\,+}}\,<\,\,{{[Cr{{(CN)}_{6}}]}^{3\,-}}\] Because the order of field strength is\[\operatorname{C}{{l}^{-}}\,N{{H}_{3}}<C{{N}^{-}}\]You need to login to perform this action.
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