A) - 0.91 V
B) +0.91 V
C) - 0.41 V
D) +0.41 V
Correct Answer: B
Solution :
Half cell reactions are \[[F{{e}^{3\,+}}+e\,\xrightarrow{{}}\,\,F{{e}^{2\,+}},\,\,E_{F{{e}^{3+}}/F{{e}^{2+}}}^{{}^\circ }=0.77\,\,V]\,\,\times \,\,2\] \[\operatorname{Sn}\,\,\xrightarrow{{}}\,\,S{{n}^{2+}}+\,\,2e, \,E_{Sn/S{{n}^{2\,+}}}^{{}^\circ }=\,\,+\,\,0.14\,V\] Adding Eqs. (i) and (ii), we get \[2F{{e}^{3\,+}}+\,\,Sn\,\xrightarrow{{}}\,\,2F{{e}^{2\,+}}+Sn\] \[E_{cell}^{{}^\circ }=0.77+0.14V=0.91V\]You need to login to perform this action.
You will be redirected in
3 sec