A) 5 M
B) 50 M
C) 0.005 M
D) 0.5 M
Correct Answer: C
Solution :
\[0.9 g{{L}^{-}}^{1}\] means 1000 mL solution contains glucose \[= \,0.9 g\] \[=\,\,\frac{0.9}{180}\,mol=5\times {{10}^{-}}^{3}\,mol\] i.e., 1 L solution contains 0.005 mole glucose or the molarity of glucose is 0.005 M.You need to login to perform this action.
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