A)
B)
C)
D)
Correct Answer: D
Solution :
The maximum kinetic energy of photoelectron ejected is given by \[\operatorname{KE}=\,\,h\nu -W\,\,=\,\,h\nu -\,\,h{{\nu }_{0}}\]where, work function depends on the type of material. If the frequency of incident radiation is greater than \[{{\nu }_{0}}\] only then the ejection of photoelectrons start. After that as frequency increases kinetic energy also increases.You need to login to perform this action.
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