A) \[R=v\sqrt{\frac{2h}{g}}\]
B) \[R=v\sqrt{\frac{h}{2g}}\]
C) \[R=\frac{av}{A}\sqrt{\frac{2h}{g}}\]
D) \[R=\frac{Av}{a}\sqrt{\frac{2h}{g}}\]
Correct Answer: D
Solution :
Let v be the horizontal speed of water when it emerges from the nozzle. From the equation of continuity, we have \[\operatorname{AV}=\,\,av\,\,\,or\,\,v=\,\,\frac{AV}{a}\] ... (i) Let t be the time taken by the stream of water to strike the ground. The horizontal and vertical distances covered in time t are \[\operatorname{R}=vt\] ... (ii) \[h=\frac{1}{2}\] ... (iii) From Eq. (iii), we have \[t=\sqrt{\frac{2h}{g}}\] Using this value in Eq. (ii), we get \[R=v\sqrt{\frac{2h}{g}}\] ... (iv) Using Eqs. (i) and (iv), we have \[R=\frac{AV}{a}\sqrt{\frac{2h}{g}}\]You need to login to perform this action.
You will be redirected in
3 sec