A) \[BC{{l}_{3}}\,\,>\,\,B{{F}_{3}}\,\,>\,\,BB{{r}_{3}}\]
B) \[BB{{r}_{3}}\,\,>\,\,BC{{l}_{3}}\,\,>\,\,B{{F}_{3}}\]
C) \[BB{{r}_{3}}\,\,>\,\,B{{F}_{3}}\,\,>\,\,BC{{l}_{3}}\]
D) \[B{{F}_{3}}\,\,>\,\,BC{{l}_{3}}\,\,>\,\,BB{{r}_{3}}\]
Correct Answer: B
Solution :
[b] p-p overlap between B and F is maximum due to identical size and energy of p- orbitals, so electron deficiency in boron of \[B{{F}_{3}}\] is neutralized partially to the maximum extent by back donation. Hence \[B{{F}_{3}}\] is least acidic.You need to login to perform this action.
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