A) \[\frac{mgl}{2AY}\]
B) \[\frac{2mgl}{AY}\]
C) \[\frac{mgl}{AY}\]
D) \[\frac{mgY}{A\ell }\]
Correct Answer: C
Solution :
[c] \[Y=\frac{F\ell }{A\Delta \ell }\]\[\Rightarrow \]\[\Delta \ell =\frac{F\ell }{YA}=\frac{mg\ell }{YA}\]You need to login to perform this action.
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