A) \[312.5\times {{10}^{-3}}\]cm
B) \[312.5\times {{10}^{-6}}\]m
C) \[312.5\times {{10}^{-3}}\]m
D) \[312.5\times {{10}^{-6}}\]cm
Correct Answer: A
Solution :
[a] Width of central maximum \[=\frac{2\,\lambda \,D}{a}=\frac{2\times 6250\times {{10}^{-10}}\times 0.5}{2\times {{10}^{-4}}}\] \[=3125\times {{10}^{-6}}m=312.5\times {{10}^{-3}}\,\,cm.\] (Screen position of various minima for Fraunh offer diffraction pattern of a single slit of width a).You need to login to perform this action.
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