A) 2 : 1
B) 3 : 1
C) 4 : 1
D) 1 : 1
Correct Answer: B
Solution :
[b] The bullets are fired at the same initial speed \[\frac{H}{H'}=\frac{{{u}^{2}}\,{{\sin }^{2}}\,60{}^\circ }{2\,g}\times \frac{2\,g}{{{u}^{2}}\,{{\sin }^{2}}\,30{}^\circ }=\frac{{{\sin }^{2}}\,60{}^\circ }{{{\sin }^{2}}\,30{}^\circ }\] \[=\frac{{{(\sqrt{3}/2)}^{2}}}{{{(1/2)}^{2}}}=\frac{3}{1}\]You need to login to perform this action.
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