A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: B
Solution :
[b] Distance in last two second \[\frac{1}{2}\times 10\times 2=10\,m.\] Total distance \[\frac{1}{2}\times 10\times (6+2)=40\,m.\]You need to login to perform this action.
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