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NEET Sample Paper NEET Sample Test Paper-85

  • question_answer
    A tin nucleus (atomic number Z = 50) has a radius of \[6.6\times {{10}^{-15}}m.\] The potential on its surface will be (the charge on the proton \[=1.6\times {{10}^{-19}}C\])

    A) \[1.1\times {{10}^{7}}\,V\]      

    B)        \[2.1\times {{10}^{7}}\,V\]

    C) \[3.1\times {{10}^{7}}\,V\]      

    D)        \[0.15\times {{10}^{7}}\,V\]

    Correct Answer: A

    Solution :

    [a] Charge on the tin nucleus = n.Q \[=(1.6\times {{10}^{-19}}\times 50)C=8\times {{10}^{-18}}C\] This charge is supposed to be concentrated at its centre. Hence, potential on the surface, \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{q}{r}\] \[=\frac{9\times {{10}^{9}}\times 8\times {{10}^{-18}}}{6.6\times {{10}^{-15}}}=1.1\times {{10}^{7}}\,\,V\]


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