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NEET Sample Paper NEET Sample Test Paper-85

  • question_answer
    A photon collides with a stationary hydrogen atom in ground state in elastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom in elastically with an energy of 15 eV. What will be observed by the detector?

    A) 2 photon of energy 10.2 eV

    B) 2 photon of energy 1.4 eV

    C) One photon of energy 10.2 eV and an electron of energy 1.4 eV

    D) One photon of energy 10.2 eV and another photon of 1.4 eV

    Correct Answer: C

    Solution :

    [c] \[13.6\,\,eV\] energy needed to liberate the electron form hydrogen atom. So electron will liberate with kinetic energy\[=15-13.6=1.4\,\,eV.\]


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