A) 5
B) 4
C) 7
D) 3
Correct Answer: D
Solution :
[d] \[V=\frac{{{V}_{0}}}{T/4}t\]\[\Rightarrow \]\[V=\frac{4{{V}_{0}}}{T}t\] \[\Rightarrow {{V}_{rms}}=\sqrt{<{{v}^{2}}>}=\frac{4{{V}_{0}}}{T}\sqrt{<{{t}^{2}}>}\] \[=\frac{4{{V}_{0}}}{T}{{\left\{ \frac{\int\limits_{0}^{T/4}{{{T}^{2}}dt}}{\int\limits_{0}^{T/4}{dt}} \right\}}^{1/2}}=\frac{{{V}_{0}}}{\sqrt{3}}\]
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