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NEET Sample Paper NEET Sample Test Paper-85

  • question_answer
    A 2 kg copper block is heated to \[500{}^\circ C\] and then it is placed on a large block of ice at \[0{}^\circ C.\] If the specific heat capacity of copper is \[400\,J/kg{}^\circ C\] and latent heat of fusion of water is \[3.5\times {{10}^{5}}J/kg,\]the amount of ice that can melt is

    A) (7/8) kg 

    B)        (7/5) kg

    C) (8/7) kg

    D)        (5/7) kg

    Correct Answer: C

    Solution :

    [c] Let x kg of ice can melt Using law of Calorimetry, Heat lost by copper = Heat gained by ice \[2\times 400\times (500-0)=x\times 3.5\times {{10}^{5}}\] or \[x=\frac{2\times 400\times 500}{3.5\times {{10}^{5}}}=\frac{8}{7}kg\]


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