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NEET Sample Paper NEET Sample Test Paper-85

  • question_answer
    The internal resistance of a 2.1V cell which gives a current of 0.2 A through a resistance of \[10\Omega \]is

    A) \[0.5\,\Omega \] 

    B)        \[0.8\,\Omega \]

    C) \[1.0\,\Omega \] 

    D)        \[0.2\,\Omega \]

    Correct Answer: A

    Solution :

    [a] Given : emf\[\varepsilon =2.1\,\,V\] \[I=0.2A,\]\[R=10\Omega \] Internal resistance r =? From formula. \[\varepsilon -Ir=V=IR\] \[2.1-0.2r=0.2\times 10\] \[2.1-0.2\,\,r=2\]or \[0.2\,r=0.1\] \[\Rightarrow \]\[r=\frac{0.1}{0.2}=0.5\,\Omega \]


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