A) \[1.8\times {{10}^{1}}\,J\]
B) \[1.8\times {{10}^{2}}\,J\]
C) \[1.0\times {{10}^{-1}}\,J\]
D) \[1.8\times {{10}^{-2}}\,J\]
Correct Answer: D
Solution :
[d] Surface tension of solution \[(T)=30\times {{10}^{-12}}\,\,N/m\] Radius of the soap bubble (r) = 5 cm = 0.05 m Since, the bubble has two spherical surface, hence, \[\Delta A=2\times \] surface area \[=2\times 4\pi {{r}^{2}}\] Therefore, surface energy \[=T\times \Delta A\] \[=30\times {{10}^{-2}}\times 2\times [4\pi \,\,{{(0.05)}^{2}}]\] \[=1.8\times {{10}^{-2}}\,\,J\]
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