A) \[0\mu C\]
B) \[4\mu C\]
C) \[16\mu C\]
D) \[8\mu C\]
Correct Answer: D
Solution :
[d] As capacitor offers infinite resistance in de- circuit. So, current flows through \[2\Omega \] resistance from left to right, given by \[I=\frac{V}{R+r}=\frac{2.5\,\,V}{2+0.5}=\frac{2.5}{2.5}=1\,\,A\] So, the potential difference across \[2\Omega \] resistance \[V=IR=1\times 2=2\,\,volt.\] Since, capacitor is in parallel with \[2\Omega \] resistance, so it also has 2V potential difference across it. As current does not flow through capacitor branch so no potential drop will be across \[10\Omega \]resistance? The charge on capacitor \[q=CV=(4\mu F)\times 2V=8\mu C\]
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