A) 557 J
B) 1450 J
C) 1050 J
D) 1296 J
Correct Answer: B
Solution :
[b] After 3 sec its velocity \[{{v}^{2}}={{u}^{2}}+2gh=0+2\times 10\times 45\] \[K.E=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 3\times 2\times 10\times 45\] \[=145\times 10=1450J.\]You need to login to perform this action.
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