| (i) \[C{{H}_{3}}C{{H}_{2}}Br+{{H}_{2}}O\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}OH\] |
| (ii) \[C{{H}_{3}}C{{H}_{2}}Br+A{{g}_{2}}O\](in boiling water)\[\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}OH\] |
A) by (i) reaction
B) by (ii) reaction
C) Both reactions proceed at same rate
D) by none
Correct Answer: B
Solution :
[b] Heavy metal ions, particularly \[A{{g}^{+}},\] catalyse \[{{S}_{N}}1\] reaction because of presence of empty orbital. \[C{{H}_{3}}C{{H}_{2}}Br+A{{g}^{+}}\] \[{{[C{{H}_{3}}C{{H}_{2}}....Br....Ag]}^{+}}\] \[\xrightarrow[(-AgBr)]{slow}c{{h}_{3}}ch_{2}^{+}\xrightarrow[From\,\,{{H}_{2}}O]{O{{H}^{-}}}C{{H}_{3}}C{{H}_{2}}OH\]
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