A) \[+1.66\,\,V\]
B) \[-1.66\,\,V\]
C) \[+2.34\,\,V\]
D) \[-2.3\,\,V\]
Correct Answer: B
Solution :
[b] The given statement explains that Al is placed above Cu in E.C.S. hence it can reduce Cu from its salt solution (reduction). Thus Al acts as a reducing agent now, Given : electrode potential of copper \[({{E}^{0}}_{cell})=+\,0.34\,\,V\] e.m.f of cell\[=2\,\,V\] We know that, emf of a galvanic cell \[({{E}^{0}}\,\,cell)\] = electrode potential of Cu (cathode) - electrode potential of Al (anode) \[2.0=0.34-{{E}^{0}}_{A1}\] \[{{E}^{0}}_{A1}=0.34-2.00=-1.66\,\,V\] Hence, electrode potential of Al is \[-1.66\,\,V.\] Option [b] is correct.You need to login to perform this action.
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