A) large size of silicon.
B) more electropositive nature of silicon.
C) availability of d-orbitals in silicon.
D) Both [a] and [b]
Correct Answer: C
Solution :
[c] Due to non-availability of vacant d-orbitals, it cannot exceed its coordination number more than four. Thus carbon never forms complexes e.g., \[{{[CC{{l}_{6}}]}^{2-}}\]does not exist but \[{{[SiC{{l}_{6}}]}^{2-}}\] exists.
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