NEET Sample Paper NEET Sample Test Paper-85

  • question_answer
    If the energy difference between the ground state of an atom and its excited state is\[4.4\times {{10}^{-4}}J,\] the wavelength of photon required to produce the transition :

    A) \[2.26\times {{10}^{-22}}m\]

    B)        \[1.13\times {{10}^{-22}}m\]

    C) (e) \[4.52\times {{10}^{-26}}m\]

    D)        \[4.52\times {{10}^{-22}}m\]

    Correct Answer: D

    Solution :

    [d] Given \[\Delta E=4.4\times {{10}^{-4}}j,\]\[\lambda =?\] \[\lambda =\frac{hc}{\Delta E}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.4\times {{10}^{-4}}}=4.5\times {{10}^{-22}}\,m\]


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