A) 0.5 kg
B) 0.15 kg
C) 0.12 kg
D) 1.5 kg
Correct Answer: A
Solution :
[a] \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}\] \[\Rightarrow \]\[m{{v}^{2}}=k{{x}^{2}}\] or \[m\times {{(1.5)}^{2}}=50\times {{(0.15)}^{2}}\] \[\therefore \]\[m=0.5\,\,kg\]
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