A) 0.2 g
B) 0.4 g
C) 2 g
D) 4 g
Correct Answer: A
Solution :
[a] We know that, \[g=\frac{GM}{{{R}^{2}}}=\frac{G\left( \frac{4}{3}\pi {{R}^{3}} \right)\rho }{{{R}^{2}}}=\frac{4}{3}\pi GR\rho \] \[\frac{g'}{g}=\frac{R'}{R}=\frac{0.2R}{R}=0.2\] \[\therefore \]\[g'=0.2\,g\]You need to login to perform this action.
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