A) \[2\pi /b\]
B) \[2\pi /\sqrt{b}\]
C) \[\sqrt{2\pi /b}\]
D) 0\[2\sqrt{\pi /b}\]
Correct Answer: B
Solution :
[b] \[T=2\,\pi \sqrt{\frac{\text{displacement}}{\text{acceleration}}}\] \[=2\pi \sqrt{\frac{x}{bx}}=2\pi /\sqrt{b}\]You need to login to perform this action.
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