A) \[\sqrt{R}\]
B) \[\sqrt{gR}\]
C) \[\sqrt{2.5gR}\]
D) \[\sqrt{7.1gR}\]
Correct Answer: B
Solution :
[b] Loss in potential energy = Gainjn kinetic energy \[-\frac{GMm}{R}-\left( -\frac{3}{2}\frac{GMm}{R} \right)=\frac{1}{2}m{{v}^{2}}\] \[\Rightarrow \]\[\frac{GMm}{2R}=\frac{1}{2}m{{v}^{2}}\]\[\Rightarrow \]\[v=\sqrt{\frac{GM}{R}}=\sqrt{gR}\]You need to login to perform this action.
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